1776=-16t^2+2717

Solution for 1776=-16t^2+2717 equation:

1776=-16t^2+2717

We move all terms to the left:

1776-(-16t^2+2717)=0

We get rid of parentheses

16t^2-2717+1776=0

We add all the numbers together, and all the variables

16t^2-941=0

a = 16; b = 0; c = -941;
Δ = b2-4ac
Δ = 02-4·16·(-941)
Δ = 60224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60224}=\sqrt{64*941}=\sqrt{64}*\sqrt{941}=8\sqrt{941}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{941}}{2*16}=\frac{0-8\sqrt{941}}{32}
=-\frac{8\sqrt{941}}{32}
=-\frac{\sqrt{941}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{941}}{2*16}=\frac{0+8\sqrt{941}}{32}
=\frac{8\sqrt{941}}{32}
=\frac{\sqrt{941}}{4}
$